Математика 6 класс учебник Виленкин, Жохов 1 часть ответы – номер 2.210

а) (12 1⁽⁴/3 − 11 1⁽³/4) + (14 − 9 8/15) = (12 4/12 − 11 3/12) + (13 15/15 − 9 8/15) = 1 1⁽⁵/12 + 4 7⁽⁴/15 = 1 5/60 + 4 28/60 = 5 33/60 = 5 11/20 б) (15 − 12 5/8) − (13 1⁽⁹/2 − 11 2⁽²/9) = (14 8/8 − 12 5/8) − (13 9/18 − 11 4/18) = 2 3⁽⁹/8 − 2 5⁽⁴/18 = 2 27/72 − 2 20/72 = 7/72
в) (14 2/3 − 5 5/9) − (3 7/8 + 4 5/6) + (10 3/4 − 4 4/9) = 6 17/24 1) 14 2⁽³/3 − 5 5/9 = 14 6/9 − 5 5/9 = 9 1/9 2) 3 7⁽³/8 + 4 5⁽⁴/6 = 3 21/24 + 4 20/24 = 7 41/24 = 8 17/24 3) 10 3⁽⁹/4 − 4 4⁽⁴/9 = 10 27/36 − 4 16/36 = 6 11/36 4) 9 1⁽⁸/9 − 8 17⁽³/24 = 9 8/72 − 8 51/72 = 8 80/72 − 8 51/72 = 29/72 5) 29/72 + 6 11⁽²/36 = 29/72 + 6 22/72 = 6 51/72 = 6 17/24
г) (14 5/7 − 14) + (30 − 29 5/7) + (3 1/7 − 23/28) = 3 9/28 1) 14 5/7 − 14 = 5/7 2) 30 − 29 5/7 = 29 7/7 − 29 5/7 = 2/7 3) 3 1⁽⁴/7 − 23/28 = 3 4/28 − 23/28 = 2 32/28 − 23/28 = 2 9/28 4) 5/7 + 2/7 + 2 9/28 = 7/7 + 2 9/28 = 1 + 2 9/28 = 3 9/28