Алгебра 9 класс учебник Макарычев, Миндюк ответы – номер 594

a) b₁ = 48
q = 12 : 48 = 1/4
b₆ = b₁q⁵ = 48 · (1/4)⁵ = 3/64
b_n = b₁q^{n - 1}
b_n = 48 · (1/4)^{n - 1} = 48 · 4^{1 - n}

б) b₁ = 64/9
q = –32/3 : 64/9 = –32/3 · 9/64 = –3/2
b₆ = b₁q⁵ = 64/9 · (–3/2)⁵ = $$\frac{2^6}{3^2}$$ · (–$$\frac{3^5}{2^5}$$ )= –2 · 3³ = –54
b_n = b₁q^{n - 1}
b_n = 64/9 · (–3/2 )^{n - 1}

в) b₁ = –0,001
q = –0,01 : (–0,001) = 10
b₆ = b₁q⁵
b₆ = –0,001 · 10⁵ = –100
b_n = b₁^{n - 1}
b_n = –0,001 · 10^{n - 1}

г) b₁ = –100
q = 10 : (–100) = –0,1
b₆ = b₁q⁵ = –100 · (–0,1)⁵ = –100 · (–0,00001) = 0,001
b_n = b₁q^{n - 1}
b_n = –100 · (–0,1)^{n - 1}