Алгебра 8 класс учебник Макарычев, Миндюк ответы – номер 836

а) $$ \left\{\begin{array} { l } { - k + b = 3 } \\ { 2 k + b = - 2 } \end{array} \left\{\begin{array} { l } { b = 3 + k } \\ { 2 k + 3 + k = - 2 } \end{array} \left\{\begin{array} { l } { b = 3 + k } \\ { 3 k = - 5 } \end{array} \left\{\begin{array} { l } { b = 3 + k } \\ { k = - \frac { 5 } { 3 } } \end{array} \left\{\begin{array}{l} b=3-1 \frac{2}{3}=1 \frac{1}{3}=\frac{4}{3} \\ k=-\frac{5}{3} \end{array}\right.\right.\right.\right.\right. $$
     y = −5/3x + 4/3
б) $$ \left\{\begin{array} { l } { 4 k + b = 1 } \\ { - 3 k + b = - 1 } \end{array} \left\{\begin{array} { l } { b = 1 - 4 k } \\ { - 3 k + 1 - 4 k = - 1 } \end{array} \left\{\begin{array} { l } { b = 1 - 4 k } \\ { - 7 k = - 2 } \end{array} \left\{\begin{array} { l } { b = 1 - 4 k } \\ { k = \frac { 2 } { 7 } } \end{array} \left\{\begin{array}{l} b=1-4 \frac{2}{7}=-\frac{1}{7} \\ k=\frac{2}{7} \end{array}\right.\right.\right.\right.\right. $$
     y = 2/7x − 1/7
в) $$ \left\{\begin{array} { l } { 0 k + b = 5 } \\ { 4 k + b = 0 } \end{array} \left\{\begin{array} { l } { b = 5 } \\ { 4 k + 5 = 0 } \end{array} \left\{\begin{array} { l } { b = 5 } \\ { 4 k = - 5 } \end{array} \left\{\begin{array}{l} b=5 \\ k=-\frac{5}{4} \end{array}\right.\right.\right.\right. $$
     y = −5/4x + 5
г) $$ \left\{\begin{array} { l } { - 3 k + b = 0 } \\ { 0 k + b = - 6 } \end{array} \left\{\begin{array} { l } { b = - 6 } \\ { - 3 k - 6 = 0 } \end{array} \left\{\begin{array} { l } { b = - 6 } \\ { - 3 k = 6 } \end{array} \left\{\begin{array}{l} b=-6 \\ k=-2 \end{array}\right.\right.\right.\right. $$
     y = −2x − 6