Алгебра 8 класс учебник Макарычев, Миндюк ответы – номер 457

а) $$\sqrt{5x − 10}$$ = $$\sqrt{5 ⋅ 2 − 10}$$ = $$\sqrt{10 − 10}$$ = $$\sqrt{0}$$ = 0 $$\sqrt{5x − 10}$$ = $$\sqrt{5 ⋅ 2,2 − 10}$$ = $$\sqrt{11 − 10}$$ = $$\sqrt{1}$$ = 1 $$\sqrt{5x − 10}$$ = $$\sqrt{5 ⋅ 5,2 − 10}$$ = $$\sqrt{26 − 10}$$ = $$\sqrt{16}$$ = 4 $$\sqrt{5x − 10}$$ = $$\sqrt{5 ⋅ 22 − 10}$$ = $$\sqrt{110 − 10}$$ = $$\sqrt{100}$$ = 10
б) $$\sqrt{6 − 2y}$$ = $$\sqrt{6 − 2 ⋅ 1}$$ = $$\sqrt{6 − 2}$$ = $$\sqrt{4}$$ = 2 $$\sqrt{6 − 2y}$$ = $$\sqrt{6 − 2 ⋅ (−1,5)}$$ = $$\sqrt{6 + 3}$$ = $$\sqrt{9}$$ = 3 $$\sqrt{6 − 2y}$$ = $$\sqrt{6 − 2 ⋅ (−1,5)}$$ = $$\sqrt{6 + 30}$$ = $$\sqrt{36}$$ = 6 $$\sqrt{6 − 2y}$$ = $$\sqrt{6 − 2 ⋅ (−37,5)}$$ = $$\sqrt{6 + 75}$$ = $$\sqrt{81}$$ = 9
в) $$ \frac{3+\sqrt{x}}{3-\sqrt{x}}=\frac{3+\sqrt{0}}{3-\sqrt{0}} $$ = 3 + 0/3 − 0 = 3/3 = 1 $$ \frac{3+\sqrt{x}}{3-\sqrt{x}}=\frac{3+\sqrt{1}}{3-\sqrt{1}} $$ = 3 + 1/3 − 1 = 4/2 = 2 $$ \frac{3+\sqrt{x}}{3-\sqrt{x}}=\frac{3+\sqrt{16}}{3-\sqrt{16}}= $$ = 3 + 4/3 − 4 = 7/−1 = −7 $$ \frac{3+\sqrt{x}}{3-\sqrt{x}}=\frac{3+\sqrt{0,25}}{3-\sqrt{0,25}} $$ = 3 + 0,5/3 − 0,5 = 3,5/2,5 = 35/25 = 7/5 = 1,4
г) $$\sqrt{2a − b}$$ = $$\sqrt{2 ⋅ 0 − 0}$$ = $$\sqrt{0}$$ $$\sqrt{2a − b}$$ = $$\sqrt{2 ⋅ 4 − 7}$$ = $$\sqrt{1}$$ = 1