Алгебра 8 класс учебник Макарычев, Миндюк ответы – номер 406

а) 2$$\sqrt{2}$$ = $$\sqrt{2² ⋅ 2}$$ = $$\sqrt{4 ⋅ 2}$$ = $$\sqrt{8}$$
б) 5$$\sqrt{y}$$ = $$\sqrt{5² ⋅ y}$$ = $$\sqrt{25 ⋅ y}$$ = $$\sqrt{25y}$$
в) −7$$\sqrt{3}$$ = −$$\sqrt{7² ⋅ 3}$$ = −$$\sqrt{49 ⋅ 3}$$ = −$$\sqrt{147}$$
г) −6$$\sqrt{2a}$$ = −$$\sqrt{6² ⋅ 2a}$$ = −$$\sqrt{36 ⋅ 2a}$$ = −$$\sqrt{72a}$$
д) 1/3$$\sqrt{18b}$$ = $$ \sqrt{\left(\frac{1}{3}\right)^2 \square 8 b}=\sqrt{\frac{1 \square 8 b}{9}}=\sqrt{\frac{18 b \div 9}{9 \div 9}} $$ = $$\sqrt{2b}$$
е) −0,1$$\sqrt{200c}$$ = −$$\sqrt{0,1² ⋅ 200c}$$ = −$$\sqrt{0,01 ⋅ 200c}$$ = −$$\sqrt{2c}$$