Алгебра 8 класс учебник Макарычев, Миндюк ответы – номер 367

- Тип: ГДЗ, Решебник.
- Авторы: Макарычев Ю.Н., Миндюк Н.Г., Нешков К.И.
- Часть: без частей.
- Год: 2019-2024.
- Серия: Школа России (ФГОС).
- Издательство: Просвещение.

Номер 367.
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Номер 367.
Вычислите значение корня:
а) $$\sqrt{810 ⋅ 40}$$
б) $$\sqrt{10 ⋅ 250}$$
в) $$\sqrt{72 ⋅ 32}$$
г) $$\sqrt{8 ⋅ 98}$$
д) $$\sqrt{50 ⋅ 18}$$
е) $$\sqrt{2,5 ⋅ 14,4}$$
ж) $$\sqrt{90 ⋅ 6,4}$$
з) $$\sqrt{16,9 ⋅ 0,4}$$
а) $$\sqrt{810 ⋅ 40}$$ = $$\sqrt{81 ⋅ 10 ⋅ 40}$$ = $$\sqrt{81 ⋅ 400}$$ = $$\sqrt{81}$$ ⋅ $$\sqrt{400}$$ = 9 ⋅ 20 = 180
б) $$\sqrt{10 ⋅ 250}$$ = $$\sqrt{10 ⋅ 10 ⋅ 250}$$ = $$\sqrt{100 ⋅ 25}$$ = $$\sqrt{100}$$ ⋅ $$\sqrt{25}$$ = 10 ⋅ 5 = 50
в) $$\sqrt{72 ⋅ 32}$$ = $$\sqrt{9 ⋅ 8 ⋅ 8 ⋅ 4}$$ = $$\sqrt{9 ⋅ 4 ⋅ 8 ⋅ 8}$$ = $$\sqrt{36 ⋅ 64}$$ = $$\sqrt{36}$$ ⋅ $$\sqrt{64}$$ = 6 ⋅ 8 = 48
г) $$\sqrt{8 ⋅ 98}$$ = $$\sqrt{8 ⋅ 2 ⋅ 49}$$ = $$\sqrt{16 ⋅ 49}$$ = $$\sqrt{16}$$ ⋅ $$\sqrt{49}$$ = 4 ⋅ 7 = 28
д) $$\sqrt{50 ⋅ 18}$$ = $$\sqrt{25 ⋅ 2 ⋅ 18}$$ = $$\sqrt{25 ⋅ 36}$$ = $$\sqrt{25}$$ ⋅ $$\sqrt{36}$$ = 5 ⋅ 6 = 30
е) $$\sqrt{2,5 ⋅ 14,4}$$ = $$\sqrt{25 ⋅ 0,1 ⋅ 0,1 ⋅ 144}$$ = $$\sqrt{25 ⋅ 0,01 ⋅ 144}$$ = $$\sqrt{25}$$ ⋅ $$\sqrt{0,01}$$ ⋅ $$\sqrt{144}$$ = 5 ⋅ 0,1 ⋅ 12 = 6
ж) $$\sqrt{90 ⋅ 6,4}$$ = $$\sqrt{9 ⋅ 10 ⋅ 6,4}$$ = $$\sqrt{9 ⋅ 64}$$ = $$\sqrt{9}$$ ⋅ $$\sqrt{64}$$ = 3 ⋅ 8 = 24
з) $$\sqrt{16,9 ⋅ 0,4}$$ = $$\sqrt{169 ⋅ 0,1 ⋅ 0,1 ⋅ 4}$$ = $$\sqrt{169 ⋅ 0,1 ⋅ 0,1 ⋅ 4}$$ = $$\sqrt{169}$$ ⋅ $$\sqrt{0,01}$$ ⋅ $$\sqrt{4}$$ = 13 ⋅ 0,1 ⋅ 2 = 2,6
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