Алгебра 8 класс учебник Макарычев, Миндюк ответы – номер 365

а) $$\sqrt{9 ⋅ 64 ⋅ 0,25}$$ = $$\sqrt{9}$$ ⋅ $$\sqrt{64}$$ ⋅ $$\sqrt{0,25}$$ = 3 ⋅ 8 ⋅ 0,5 = 12
б) $$\sqrt{1,21 ⋅ 0,09 ⋅ 0,0001}$$ = $$\sqrt{1,21}$$ ⋅ $$\sqrt{0,09}$$ ⋅ $$\sqrt{0,0001}$$ = 1,1 ⋅ 0,3 ⋅ 0,01 = 0,0033
в) $$ \sqrt{\frac{25}{81}-\frac{16}{49}-\frac{196}{9}}=\sqrt{\frac{25}{81}} \sqrt{\frac{16}{49}} \sqrt{\frac{196}{9}} $$ = 5/9 ⋅ 4/7 ⋅ 14/3 = 5 ⋅ 4 ⋅ 14/9 ⋅ 7 ⋅ 3 = 5 ⋅ 4 ⋅ 14 : 7/9 ⋅ 7 ⋅ 3 : 7 = 40/27 = 113/40
г) $$ \sqrt{5 \frac{1}{16} \square \frac{34}{81}}=\sqrt{\frac{5 \square 6+1}{16}} \square \sqrt{\frac{281+34}{81}}=\sqrt{\frac{81}{16} \frac{196}{81}}=\sqrt{\frac{81 \square 96}{16 \square 81}} $$ = $$ \sqrt{\frac{81 \square 96 \div 81}{1681 \div 81}}=\sqrt{\frac{196}{16}}=\frac{\sqrt{196}}{\sqrt{16}} $$ = 14/4 = 3,5