Алгебра 8 класс учебник Макарычев, Миндюк ответы – номер 116

- Тип: ГДЗ, Решебник.
- Авторы: Макарычев Ю.Н., Миндюк Н.Г., Нешков К.И.
- Часть: без частей.
- Год: 2019-2024.
- Серия: Школа России (ФГОС).
- Издательство: Просвещение.

Номер 116.
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Номер 116.
Упростите выражение:
а) 2a²b/3xy ⋅ 3x²y/4ab² ⋅ 6ax/15b²
б) 6m³n²/35p³ ⋅ 49n⁴/m⁵p³ ⋅ 5m⁴p²/42n⁶
а) 2a²b/3xy ⋅ 3x²y/4ab² ⋅ 6ax/15b² = 2a²b ⋅ 3x²y ⋅ 6ax/3xy ⋅ 4ab² ⋅ 15b² = 2a²b ⋅ 3x²y ⋅ 2 ⋅ 3ax : (2 ⋅ 2 ⋅ 3 ⋅ 3abxy)/3xy ⋅ 4ab² ⋅ 5 ⋅ 3b² : (2 ⋅ 2 ⋅ 3 ⋅ 3abxy) = a²x²/5b³
б) 6m³n²/35p³ ⋅ 49n⁴/m⁵p³ ⋅ 5m⁴p²/42n⁶ = 6m³n² ⋅ 49n⁴ ⋅ 5m⁴p²/35p³ ⋅ m⁵p³ ⋅ 42n⁶ = 6m⁷n⁶ ⋅ 7 ⋅ 7 ⋅ 5p²/7 ⋅ 5 ⋅ p⁶ ⋅ m⁵ ⋅ 7 ⋅ 6 ⋅ n⁶ = 6m⁷n⁶ ⋅ 7 ⋅ 7 ⋅ 5p² : (6 ⋅ 7 ⋅ 7 ⋅ 5 ⋅ m⁵n⁶p²)/7 ⋅ 5 ⋅ p⁶ ⋅ m⁵ ⋅ 7 ⋅ 6 ⋅ n⁶ : (6 ⋅ 7 ⋅ 7 ⋅ 5 ⋅ m⁵n⁶p²) = m²/p⁴
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